Book 1 – Proposition 29

A straight line falling on parallel straight lines makes the alternate angles equal to one another, the exterior angle equal to the opposite and interior angle, and the interior angles on the same side equal to two right angles.

Let EF fall on the parallel straight lines AB and CD.

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Part 1: We will prove that the alternate angles AGH and GHD are equal.

If the two angles are not equal, then one must be greater. Let AGH be the greater angle.
Add angle BGH to both, and angles AGH and BGH are greater than angles GHD and BGH. But the angles AGH and BGH are equal to two right angles by Proposition 13 (If a straight line falls on a straight line, it makes two angles that are equal to two right angles.)
Therefore the two angles GHD and BGH are less than two right angles. Lines that produce indefinitely from angles less than two right angles meet (this is one of Euclid’s Postulates), meaning that AB and CD will meet.
But AB and CD cannot meet because they are parallel, and this contradiction implies that angle AGH cannot be greater than angle GHD.

Therefore the alternate angles AGH and GHD must be equal.


 

Part 2: We will prove that the exterior angle EGB is equal to the interior and opposite angle GHD.

In Part 1 we proved that angle AGH is equal to angle GHD.
By Proposition 15 (vertical angles are equal to each other) angle AGH is equal to angle EGB.

Therefore the exterior angle EGB is equal to the interior and opposite angle GHD.


 

Part 3: We will prove that the interior angles on the same side (BGH and GHD) are equal to two right angles.

In Part 2 we proved that angle EGB was equal to angle GHD. Add angle BGH to each, and we have that the two angles EGB and BGH are equal to the two angles GHD and BGH.

Again using Proposition 13 (a straight line that falls on a straight line produces two angles that are equal to two right angles), the two angles EGB and BGH are equal to two right angles. That implies that the two angles BGH and GHD are equal to two right angles.

Therefore the interior angles on the same side are equal to two right angles.

Q.E.D.

More fun with parallel lines in the next Proposition – George

Book 1 – Proposition 15

Proposition 15

If two straight lines cut each other, they make vertical angles equal to one another.


This proposition appears a great deal in today’s geometry & trigonometry classes: Vertical angles are equal.


Let two lines AB and CD cut each other, intersecting at point E.
We will show that angle AEC is equal to angle BED, and that angle AED is equal to angle BEC.

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Line AE lies on the straight line, so by Proposition 13 (When a straight line lies on a straight line, the two adjacent angles are equal to two right angles) the two angles AEC and AED are equal to two right angles.

Using the same reasoning, the two angles AED and BEDare equal to two right angles since the line DE lies on the straight line AB.

Since both pairs of angles are equal to two right angles, we know that the two angles AEC and AED are equal to the two angles AED and BED. Subtract the angle AED from each, and we find that angle AEC is equal to angle BED.

Can you prove that angle AED is equal to angle BEC? Try it first on your own, then click on the Proof Strategy tag below.

Please feel free to leave any questions/comments for me – George
Proof Strategy